We now learn how to split the middle term.
Splitting the middle term is a method for factoring quadratic equations.
By the end of this section we'll know how to write quadratics in factored form:
\[ax^2+bx+c = \begin{pmatrix} mx + d \end{pmatrix} \begin{pmatrix} nx + e \end{pmatrix} \]
For example, we'll know how to show that:
\[2x^2+7x+3 = \begin{pmatrix} 2x + 1 \end{pmatrix} \begin{pmatrix} x + 3 \end{pmatrix}\]
We start by watching a tutorial to learn a five-step method for factornig quadratics. We then read through the five steps
Given a quadratic: \[ax^2+bx+c\] We'll often be required to factor it. We say we write it in factored form. To do this we follow a five-step method.
The method is best explained in the following tutorial, watch it now.
In the following tutorial we learn how to factor quadratics by splitting the middle term. Watch it now.
Write each of the following quadratics in factored form:
Now that we know how to factor quadratics, by splitting the middle term, we learn how to solve quadratic equations by factoring.
The method/technique rests on the null factor law, explained here.
Given two quantities \(A\) and \(B\) such that: \[A\times B = 0\] then one of the following must be true:
Once a quadratic, \(ax^2+bx+c\), has been written in factored form, we can use the null factor law to solve the equation: \[ax^2+bx+c = 0\]
In factored form, the quadratic \(2x^2+7x+3\) can be written: \[\begin{pmatrix}2x+1 \end{pmatrix} \begin{pmatrix}x+3 \end{pmatrix}\] Consequently we can write: \[2x^2+7x+3 = 0\]
Starting with \(2x+1 = 0\):
\[\begin{aligned}
& 2x+1 = 0 \\
& 2x = -1 \\
& x = -\frac{1}{2}
\end{aligned}\]
We now solve \(x+3 = 0\):
\[\begin{aligned}
& x+3 = 0 \\
& x = -3
\end{aligned}\]
The equation \(2x^2+7x+3 = 0\) has two solutions:
In the following tutorial we learn how to solve quadratic equations that have been written in their factored form, by splitting the middle term, using the null factor law.
Solve each of the following quadratic equations by factoring (splitting the middle term):